Velvet Star Monitor

Standout celebrity highlights with iconic style.

news

$y(n) = x(-n)$ , causal or not , memory or memoryless?

Writer Sebastian Wright
$\begingroup$

$y(n) = x(-n)$ , causal or not , memory or memory-less ?

it's a question in digital signal processing course .

My guess it's memory less , causal because $x(-n)$ is only the inverse of the function ?

Memoryless System A system is memoryless if the output y[n] at every value of n depends only on the input x[n] at the same value of n

Causality A system is causal it’s output is a function of only the current and previous samples

$\endgroup$ 3

1 Answer

$\begingroup$
  • It is not causal. Consider $n=-1$. The output $y(-1)$ depends on the input at $n=1$, which is only available in future.
  • It is not memoryless. Consider any $n > 0$. The output $y$ depends on the input at $-n$ which was applied in the past. Thus the system has memory.
$\endgroup$

Your Answer

Sign up or log in

Sign up using Google Sign up using Facebook Sign up using Email and Password

Post as a guest

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy