Why sigset includes unadded SIGINT? [closed]
Mia Lopez
Wrote simple program to learn writing POSIX style signal handling.
#include <signal.h>
#include <errno.h>
#include <stdio.h>
#include <stdlib.h>
static void sig_int(int);
int
main(void)
{ sigset_t waitmask; if (signal(SIGINT, sig_int) == SIG_ERR) { printf("error occured\n"); exit(1); } sigemptyset(&waitmask); sigaddset(&waitmask, SIGUSR1); if (sigsuspend(&waitmask) != -1) { printf("error\n"); exit(1); }
}
static void
sig_int(int signo)
{ sigset_t sigset; sigprocmask(0, NULL, &sigset); if (sigismember(&sigset, SIGINT)) printf("SIGINT\n"); if (sigismember(&sigset, SIGUSR1)) printf("SIGUSR1\n");
}I create empty signal set.
Then I add SIGUSR to the sigset.
Install the signal handler
When I launch the program and it pauses waiting for the signal, I generate SIGINT, the handler prints that SIGINT also is member of the sigset, that seems to be very strange behaviour.
Why sigismember thinks that SIGINT is member of sigset, although it was not added explicitly with sigaddset(&waitmask, SIGINT)?
11 Answer
From man 2 signal:
If the disposition is set to a function, then first either the disposition is reset to SIG_DFL, or the signal is blocked (see Portability below), and then handler is called with argument signum. If invocation of the handler caused the signal to be blocked, then the signal is unblocked upon return from the handler.