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Am I right in assuming that $\lg$ just refers to $\log$ base ($10$)? Whereas $\log$ is just any unspecified log?

I'm solving $\lg{15}-\lg{5}$

Am I good to just use the standard rules of logarithms, where subtraction is concerned?

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2 Answers

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$\lg3$ is the answer :)

Because $\lg{\dfrac{15}{5}}=\lg{3}$

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In general, the use of $lg$ is ambiguous. Therefore this problem is not properly stated, it should have been explicitly mentioned what $lg$ means. Of course, if that's just an exercise after some lesson, and that lesson defines what exactly $lg$ is, then the problem is stated fine.

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