$\begingroup$

I am currently working through the Feynman Lectures, chapter 6: Probability. I have reached his problem of the "random walk".

After deriving this and getting some root mean square, wouldn't this just be the same as finding the standard deviation? The standard deviation is the root of the mean of the squared data. Isn't that also just the root mean square?

Also, what exactly are the implications of the root mean square, what does it even mean in regards to our problem?

$\endgroup$ 6

1 Answer

$\begingroup$

in the case of standard deviation, the mean is removed out from obsevations, but in root mean square the mean is not removed. however in the case of noise where the mean is zero, the two concept are the same. I hope that this is the difference. see:

$\endgroup$ 2

Your Answer

Sign up or log in

Sign up using Google Sign up using Facebook Sign up using Email and Password Submit

Post as a guest

Post Your Answer Discard

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy