Understanding the group operation $U_n$
Andrew Henderson
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In preparation of a test, there were a few things in class that still confused me on how my instructor got the answer:
Using the following definition for $U_n$:
There were two examples we did in class that I don't understand clearly:
And this one:
Order of [3] in $U_{20}$ = 4
[3]^2 = [9] [3]^3 = [7] [3]^4 = [1] [17] = [-3] = 4I would really like to know what the process is behind these examples to understand them for my test next week. If possible, how would I start with finding the order of [7] in $U_{40}$?
Thanks for reading, really appreciate the help!
$\endgroup$ 51 Answer
$\begingroup$Mod 40, we compute: 7*7 = 49 = 9, 7*7*7 = 343 = 23, 7*7*7*7 = 2401 = 1. Therefore the order of 7 is 4.
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