The exact value of csc -420 degrees (Find the exact value of each trigonometric funtion)
Matthew Barrera
I'am very confused, I have looked all over google and I can not find out how too do this problem.
I have the answer its number 14 since our teacher gives us the answer but we need to show work.
I understood number 13 it was $\sec -210^\circ$, but I can't figure out how too do #14. How can it be $-2 \sqrt{3}/ 3$? I just can't figure this problem out.
Any help would be greatly appreciated. The problem is $\csc -420^\circ$.
$\endgroup$ 12 Answers
$\begingroup$$$\csc(-420^\circ)=-\csc 420^\circ=-\csc 60^\circ=-\frac{2\sqrt3}{2}$$
$\endgroup$ 1 $\begingroup$$$ \csc(-420^\circ)= -\csc(420^\circ) \text{ since cosecant is an odd function. Thus}\\ -\csc(420^\circ) = -\csc(60^\circ) = -\frac{1}{\sin(60^\circ)} = -\frac{1}{\frac{\sqrt{3}}{2}} = -\frac{2}{\sqrt{3}}=-\frac{2\sqrt{3}}{3} $$
$\endgroup$ 3