Velvet Star Monitor

Standout celebrity highlights with iconic style.

general

The exact value of csc -420 degrees (Find the exact value of each trigonometric funtion)

Writer Matthew Barrera
$\begingroup$

I'am very confused, I have looked all over google and I can not find out how too do this problem. I have the answer its number 14 since our teacher gives us the answer but we need to show work.enter image description here

I understood number 13 it was $\sec -210^\circ$, but I can't figure out how too do #14. How can it be $-2 \sqrt{3}/ 3$? I just can't figure this problem out.

Any help would be greatly appreciated. The problem is $\csc -420^\circ$.

$\endgroup$ 1

2 Answers

$\begingroup$

$$\csc(-420^\circ)=-\csc 420^\circ=-\csc 60^\circ=-\frac{2\sqrt3}{2}$$

$\endgroup$ 1 $\begingroup$

$$ \csc(-420^\circ)= -\csc(420^\circ) \text{ since cosecant is an odd function. Thus}\\ -\csc(420^\circ) = -\csc(60^\circ) = -\frac{1}{\sin(60^\circ)} = -\frac{1}{\frac{\sqrt{3}}{2}} = -\frac{2}{\sqrt{3}}=-\frac{2\sqrt{3}}{3} $$

$\endgroup$ 3

Your Answer

Sign up or log in

Sign up using Google Sign up using Facebook Sign up using Email and Password

Post as a guest

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy