SQLAlchemy ORDER BY DESCENDING?
Sophia Terry
How can I use ORDER BY descending in a SQLAlchemy query like the following?
This query works, but returns them in ascending order:
query = (model.Session.query(model.Entry) .join(model.ClassificationItem) .join(model.EnumerationValue) .filter_by(id=c.row.id) .order_by(model.Entry.amount) # This row :) )If I try:
.order_by(desc(model.Entry.amount))then I get: NameError: global name 'desc' is not defined.
6 Answers
Just as an FYI, you can also specify those things as column attributes. For instance, I might have done:
.order_by(model.Entry.amount.desc())This is handy since it avoids an import, and you can use it on other places such as in a relation definition, etc.
For more information, you can refer this SQLAlchemy 1.4 Documentation
5from sqlalchemy import desc
someselect.order_by(desc(table1.mycol))Usage from @jpmc26
1One other thing you might do is:
.order_by("name desc")This will result in: ORDER BY name desc. The disadvantage here is the explicit column name used in order by.
7You can use .desc() function in your query just like this
query = (model.Session.query(model.Entry) .join(model.ClassificationItem) .join(model.EnumerationValue) .filter_by(id=c.row.id) .order_by(model.Entry.amount.desc()) )This will order by amount in descending order or
query = session.query( model.Entry
).join( model.ClassificationItem
).join( model.EnumerationValue
).filter_by( id=c.row.id
).order_by( model.Entry.amount.desc()
)
)Use of desc function of SQLAlchemy
from sqlalchemy import desc
query = session.query( model.Entry
).join( model.ClassificationItem
).join( model.EnumerationValue
).filter_by( id=c.row.id
).order_by( desc(model.Entry.amount)
)
)For official docs please use the link or check below snippet
1sqlalchemy.sql.expression.desc(column) Produce a descending ORDER BY clause element.
e.g.:
from sqlalchemy import desc stmt = select([users_table]).order_by(desc(users_table.c.name))will produce SQL as:
SELECT id, name FROM user ORDER BY name DESCThe desc() function is a standalone version of the ColumnElement.desc() method available on all SQL expressions, e.g.:
stmt = select([users_table]).order_by(users_table.c.name.desc())Parameters column – A ColumnElement (e.g. scalar SQL expression) with which to apply the desc() operation.
See also
asc()
nullsfirst()
nullslast()
Select.order_by()
You can try: .order_by(ClientTotal.id.desc())
session = Session()
auth_client_name = 'client3'
result_by_auth_client = session.query(ClientTotal).filter(ClientTotal.client ==
auth_client_name).order_by(ClientTotal.id.desc()).all()
for rbac in result_by_auth_client: print(rbac.id)
session.close() Complementary at @Radu answer, As in SQL, you can add the table name in the parameter if you have many table with the same attribute.
.order_by("TableName.name desc") 2