Propositional logic: WFF of "neither A nor B"
Matthew Martinez
In propositional logic, how should the sentence "neither A nor B" be converted into a Well Formed Formula? Is it $\sim(A \lor B)$ or should it be $\sim(A \land B)$? Can it be interrupted both ways? I need a little help understanding this.
$\endgroup$ 03 Answers
$\begingroup$"Neither A nor B" is "not A and not B" and is formalized with Logical NOR i.e. $(¬A ∧ ¬B)$ that is equivalent to $¬(A ∨ B)$.
You can check with a simple truth table that $¬(A ∨ B)$ and $¬(A ∧ B)$ are not equivalent [when $A$ is TRUE and $B$ is FALSE, the first formula is FALSE, while the second one is TRUE].
$\endgroup$ 6 $\begingroup$"Neither ...nor" is the negation of " OR" ; hence its name " NOR"
So neither A nor B means
- ~ (A OR B) [ read : it's not the case that (A is true OR B is true)]
which is equivalent, using DeMorgan's law, to
- ~ A & ~ B.
An Or statement is true as soon as at least one of the conjuncts is true; a NOR statement is false as soon as one of the 2 sentences is true.
$\endgroup$ $\begingroup$in order to be true , the sentence ~ ( A&B) requires that one ( at least) out of the two propositions to be false; and the falsehood of only one proposition is sufficient for ~ (A & B) to be true
the truth conditions of " neither A nor B" are different ; in order to be true, it requires BOTH propositions to be false.
since " neither A nor B" and "~ (A&B)" do not have the same truth conditions, they are not equivalent.