Velvet Star Monitor

Standout celebrity highlights with iconic style.

updates

Pandas convert data type from object to float

Writer Andrew Mclaughlin

I read some weather data from a .csv file as a dataframe named "weather". The problem is that the data type of one of the columns is object. This is weird, as it indicates temperature. How do I change it to having a float data type? I tried to_numeric, but it can't parse it.

weather.info()
weather.head()
<class 'pandas.core.frame.DataFrame'>
DatetimeIndex: 304 entries, 2017-01-01 to 2017-10-31
Data columns (total 2 columns):
Temp 304 non-null object
Rain 304 non-null float64
dtypes: float64(1), object(1)
memory usage: 17.1+ KB Temp Rain
Date
2017-01-01 12.4 0.0
2017-02-01 11 0.6
2017-03-01 10.4 0.6
2017-04-01 10.9 0.2
2017-05-01 13.2 0.0
3

6 Answers

  • You can use pandas.Series.astype
  • You can do something like this :

    weather["Temp"] = weather.Temp.astype(float)
  • You can also use pd.to_numeric that will convert the column from object to float

  • For details on how to use it checkout this link :
  • Example :

    s = pd.Series(['apple', '1.0', '2', -3])
    print(pd.to_numeric(s, errors='ignore'))
    print("=========================")
    print(pd.to_numeric(s, errors='coerce'))
  • Output:

    0 apple
    1 1.0
    2 2
    3 -3
    =========================
    dtype: object
    0 NaN
    1 1.0
    2 2.0
    3 -3.0
    dtype: float64
  • In your case you can do something like this:

    weather["Temp"] = pd.to_numeric(weather.Temp, errors='coerce')
  • Other option is to use convert_objects
  • Example is as follows

    >> pd.Series([1,2,3,4,'.']).convert_objects(convert_numeric=True)
    0 1
    1 2
    2 3
    3 4
    4 NaN
    dtype: float64
  • You can use this as follows:

    weather["Temp"] = weather.Temp.convert_objects(convert_numeric=True)
  • I have showed you examples because if any of your column won't have a number then it will be converted to NaN... so be careful while using it.

I tried all methods suggested here but sadly none worked. Instead, found this to be working:

df['column'] = pd.to_numeric(df['column'],errors = 'coerce')

And then check it using:

print(df.info())

I eventually used:

weather["Temp"] = weather["Temp"].convert_objects(convert_numeric=True)

It worked just fine, except that I got the following message.

C:\ProgramData\Anaconda3\lib\site-packages\ipykernel_launcher.py:3: FutureWarning:
convert_objects is deprecated. Use the data-type specific converters pd.to_datetime, pd.to_timedelta and pd.to_numeric.
3

You can try the following:

df['column'] = df['column'].map(lambda x: float(x))

First check your data cuz you may get an error if you have ',' instead of '.' if so, you need to transform every ',' into '.' with a function :

def replacee(s):
i=str(s).find(',')
if(i>0): return s[:i] + '.' + s[i+1:]
else : return s 

then you need to apply this function on every row in your column :

dfOPA['Montant']=dfOPA['Montant'].apply(replacee)

then the convert function will work fine :

dfOPA['Montant'] = pd.to_numeric(dfOPA['Montant'],errors = 'coerce')

Eg, For Converting $40,000.00 object to 40000 int or float32

Follow this step by step :

$40,000.00 ---(**1**. remove $)---> 40,000.00 ---(**2**. remove , comma)---> 40000.00 ---(**3**. remove . dot)---> 4000000 ---(**4**. remove empty space)---> 4000000 ---(**5**. Remove NA Values)---> 4000000 ---(**6**. now this is object type so, convert to int using .astype(int) )---> 4000000 ---(**7**. divide by 100)---> 40000 

Implementing code In Pandas

table1["Price"] = table1["Price"].str.replace('$','')<br>
table1["Price"] = table1["Price"].str.replace(',','')<br>
table1["Price"] = table1["Price"].str.replace('.','')<br>
table1["Price"] = table1["Price"].str.replace(' ','')
table1 = table1.dropna()<br>
table1["Price"] = table1["Price"].astype(int)<br>
table1["Price"] = table1["Price"] / 100<br> 

Finally it's done

1

Your Answer

Sign up or log in

Sign up using Google Sign up using Facebook Sign up using Email and Password

Post as a guest

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy