Loop through an array of strings in Bash?
Sophia Terry
I want to write a script that loops through 15 strings (array possibly?) Is that possible?
Something like:
for databaseName in listOfNames
then # Do something
end 22 Answers
You can use it like this:
## declare an array variable
declare -a arr=("element1" "element2" "element3")
## now loop through the above array
for i in "${arr[@]}"
do echo "$i" # or do whatever with individual element of the array
done
# You can access them using echo "${arr[0]}", "${arr[1]}" alsoAlso works for multi-line array declaration
declare -a arr=("element1" "element2" "element3" "element4" ) 9 That is possible, of course.
for databaseName in a b c d e f; do # do something like: echo $databaseName
done See Bash Loops for, while and until for details.
11None of those answers include a counter...
#!/bin/bash
## declare an array variable
declare -a array=("one" "two" "three")
# get length of an array
arraylength=${#array[@]}
# use for loop to read all values and indexes
for (( i=0; i<${arraylength}; i++ ));
do echo "index: $i, value: ${array[$i]}"
doneOutput:
index: 0, value: one
index: 1, value: two
index: 2, value: three 8 Yes
for Item in Item1 Item2 Item3 Item4 ; do echo $Item doneOutput:
Item1
Item2
Item3
Item4To preserve spaces; single or double quote list entries and double quote list expansions.
for Item in 'Item 1' 'Item 2' 'Item 3' 'Item 4' ; do echo "$Item" doneOutput:
Item 1
Item 2
Item 3
Item 4To make list over multiple lines
for Item in Item1 \ Item2 \ Item3 \ Item4 do echo $Item doneOutput:
Item1
Item2
Item3
Item4Simple list variable
List=( Item1 Item2 Item3 )or
List=( Item1 Item2 Item3 )Display the list variable:
echo ${List[*]}Output:
Item1 Item2 Item3Loop through the list:
for Item in ${List[*]} do echo $Item doneOutput:
Item1
Item2
Item3Create a function to go through a list:
Loop(){ for item in ${*} ; do echo ${item} done
}
Loop ${List[*]}Using the declare keyword (command) to create the list, which is technically called an array:
declare -a List=( "element 1" "element 2" "element 3" )
for entry in "${List[@]}" do echo "$entry" doneOutput:
element 1
element 2
element 3Creating an associative array. A dictionary:
declare -A continent
continent[Vietnam]=Asia
continent[France]=Europe
continent[Argentina]=America
for item in "${!continent[@]}"; do printf "$item is in ${continent[$item]} \n" doneOutput:
Argentina is in America Vietnam is in Asia France is in EuropeCSV variables or files in to a list.
Changing the internal field separator from a space, to what ever you want.
In the example below it is changed to a comma
List="Item 1,Item 2,Item 3"
Backup_of_internal_field_separator=$IFS
IFS=,
for item in $List; do echo $item done
IFS=$Backup_of_internal_field_separatorOutput:
Item 1
Item 2
Item 3If need to number them:
` this is called a back tick. Put the command inside back ticks.
`command` It is next to the number one on your keyboard and or above the tab key, on a standard American English language keyboard.
List=()
Start_count=0
Step_count=0.1
Stop_count=1
for Item in `seq $Start_count $Step_count $Stop_count` do List+=(Item_$Item) done
for Item in ${List[*]} do echo $Item doneOutput is:
Item_0.0
Item_0.1
Item_0.2
Item_0.3
Item_0.4
Item_0.5
Item_0.6
Item_0.7
Item_0.8
Item_0.9
Item_1.0Becoming more familiar with bashes behavior:
Create a list in a file
cat <<EOF> List_entries.txt
Item1
Item 2
'Item 3'
"Item 4"
Item 7 : *
"Item 6 : * "
"Item 6 : *"
Item 8 : $PWD
'Item 8 : $PWD'
"Item 9 : $PWD"
EOFRead the list file in to a list and display
List=$(cat List_entries.txt)
echo $List
echo '$List'
echo "$List"
echo ${List[*]}
echo '${List[*]}'
echo "${List[*]}"
echo ${List[@]}
echo '${List[@]}'
echo "${List[@]}"BASH commandline reference manual: Special meaning of certain characters or words to the shell.
23In the same spirit as 4ndrew's answer:
listOfNames="RA
RB
R C
RD"
# To allow for other whitespace in the string:
# 1. add double quotes around the list variable, or
# 2. see the IFS note (under 'Side Notes')
for databaseName in "$listOfNames" # <-- Note: Added "" quotes.
do echo "$databaseName" # (i.e. do action / processing of $databaseName here...)
done
# Outputs
# RA
# RB
# R C
# RDB. No whitespace in the names:
listOfNames="RA
RB
R C
RD"
for databaseName in $listOfNames # Note: No quotes
do echo "$databaseName" # (i.e. do action / processing of $databaseName here...)
done
# Outputs
# RA
# RB
# R
# C
# RDNotes
- In the second example, using
listOfNames="RA RB R C RD"has the same output.
Other ways to bring in data include:
Read from stdin
# line delimited (each databaseName is stored on a line)
while read databaseName
do echo "$databaseName" # i.e. do action / processing of $databaseName here...
done # <<< or_another_input_method_here- the bash IFS "field separator to line" [1] delimiter can be specified in the script to allow other whitespace (i.e.
IFS='\n', or for MacOSIFS='\r') - I like the accepted answer also :) -- I've include these snippets as other helpful ways that also answer the question.
- Including
#!/bin/bashat the top of the script file indicates the execution environment. - It took me months to figure out how to code this simply :)
Other Sources (while read loop)
4You can use the syntax of ${arrayName[@]}
#!/bin/bash
# declare an array called files, that contains 3 values
files=( "/etc/passwd" "/etc/group" "/etc/hosts" )
for i in "${files[@]}"
do echo "$i"
done 0 Surprised that nobody's posted this yet -- if you need the indices of the elements while you're looping through the array, you can do this:
arr=(foo bar baz)
for i in ${!arr[@]}
do echo $i "${arr[i]}"
doneOutput:
0 foo
1 bar
2 bazI find this a lot more elegant than the "traditional" for-loop style (for (( i=0; i<${#arr[@]}; i++ ))).
(${!arr[@]} and $i don't need to be quoted because they're just numbers; some would suggest quoting them anyway, but that's just personal preference.)
This is also easy to read:
FilePath=( "/tmp/path1/" #FilePath[0] "/tmp/path2/" #FilePath[1]
)
#Loop
for Path in "${FilePath[@]}"
do echo "$Path"
done 1 Simple way :
arr=("sharlock" "bomkesh" "feluda" ) ##declare array
len=${#arr[*]} # it returns the array length
#iterate with while loop
i=0
while [ $i -lt $len ]
do echo ${arr[$i]} i=$((i+1))
done
#iterate with for loop
for i in $arr
do echo $i
done
#iterate with splice echo ${arr[@]:0:3} I used this approach for my GitHub updates, and I found it simple.
## declare an array variable
arr_variable=("kofi" "kwame" "Ama")
## now loop through the above array
for i in "${arr_variable[@]}"
do echo "$i"
done You can iterate through bash array values using a counter with three-expression (C style) to read all values and indexes for loops syntax:
declare -a kofi=("kofi" "kwame" "Ama")
# get the length of the array
length=${#kofi[@]}
for (( j=0; j<${length}; j++ ));
do print (f "Current index %d with value %s\n" $j "${kofi[$j]}")
done 1 listOfNames="db_one db_two db_three"
for databaseName in $listOfNames
do echo $databaseName
doneor just
for databaseName in db_one db_two db_three
do echo $databaseName
done 0 Implicit array for script or functions:
In addition to anubhava's correct answer: If basic syntax for loop is:
for var in "${arr[@]}" ;do ...$var... ;donethere is a special case in bash:
When running a script or a function, arguments passed at command lines will be assigned to $@ array variable, you can access by $1, $2, $3, and so on.
This can be populated (for test) by
set -- arg1 arg2 arg3 ...A loop over this array could be written simply:
for item ;do echo "This is item: $item." doneNote that the reserved work in is not present and no array name too!
Sample:
set -- arg1 arg2 arg3 ...
for item ;do echo "This is item: $item." done
This is item: arg1.
This is item: arg2.
This is item: arg3.
This is item: ....Note that this is same than
for item in "$@";do echo "This is item: $item." doneThen into a script:
#!/bin/bash
for item ;do printf "Doing something with '%s'.\n" "$item" doneSave this in a script myscript.sh, chmod +x myscript.sh, then
./myscript.sh arg1 arg2 arg3 ...
Doing something with 'arg1'.
Doing something with 'arg2'.
Doing something with 'arg3'.
Doing something with '...'.Same in a function:
myfunc() { for item;do cat <<<"Working about '$item'."; done ; }Then
myfunc item1 tiem2 time3
Working about 'item1'.
Working about 'tiem2'.
Working about 'time3'. The declare array doesn't work for Korn shell. Use the below example for the Korn shell:
promote_sla_chk_lst="cdi xlob"
set -A promote_arry $promote_sla_chk_lst
for i in ${promote_arry[*]}; do echo $i done 3 Try this. It is working and tested.
for k in "${array[@]}"
do echo $k
done
# For accessing with the echo command: echo ${array[0]}, ${array[1]} 2 This is similar to user2533809's answer, but each file will be executed as a separate command.
#!/bin/bash
names="RA
RB
R C
RD"
while read -r line; do echo line: "$line"
done <<< "$names" If you are using Korn shell, there is "set -A databaseName ", else there is "declare -a databaseName"
To write a script working on all shells,
set -A databaseName=("db1" "db2" ....) || declare -a databaseName=("db1" "db2" ....)
# now loop
for dbname in "${arr[@]}"
do echo "$dbname" # or whatever
doneIt should be work on all shells.
1What I really needed for this was something like this:
for i in $(the_array); do something; doneFor instance:
for i in $(ps -aux | grep vlc | awk '{ print $2 }'); do kill -9 $i; done(Would kill all processes with vlc in their name)
How you loop through an array, depends on the presence of new line characters. With new line characters separating the array elements, the array can be referred to as "$array", otherwise it should be referred to as "${array[@]}". The following script will make it clear:
#!/bin/bash
mkdir temp
mkdir temp/aaa
mkdir temp/bbb
mkdir temp/ccc
array=$(ls temp)
array1=(aaa bbb ccc)
array2=$(echo -e "aaa\nbbb\nccc")
echo '$array'
echo "$array"
echo
for dirname in "$array"; do echo "$dirname"
done
echo
for dirname in "${array[@]}"; do echo "$dirname"
done
echo
echo '$array1'
echo "$array1"
echo
for dirname in "$array1"; do echo "$dirname"
done
echo
for dirname in "${array1[@]}"; do echo "$dirname"
done
echo
echo '$array2'
echo "$array2"
echo
for dirname in "$array2"; do echo "$dirname"
done
echo
for dirname in "${array2[@]}"; do echo "$dirname"
done
rmdir temp/aaa
rmdir temp/bbb
rmdir temp/ccc
rmdir temp Possible first line of every Bash script/session:
say() { for line in "${@}" ; do printf "%s\n" "${line}" ; done ; }Use e.g.:
$ aa=( 7 -4 -e ) ; say "${aa[@]}"
7
-4
-eMay consider: echo interprets -e as option here
Single line looping,
declare -a listOfNames=('db_a' 'db_b' 'db_c') for databaseName in ${listOfNames[@]}; do echo $databaseName; done;you will get an output like this,
db_a
db_b
db_c Declare an array of string with type
declare -a StringArray=("Linux Mint" "Fedora" "Red Hat Linux" "Ubuntu" "Debian" )Iterate the string array using for loop
for val in ${StringArray[@]}; do echo $val
doneOutput
I loop through an array of my projects for a git pull update:
#!/bin/sh
projects="
web
ios
android
"
for project in $projects do cd $HOME/develop/$project && git pull
end 2