How to simplify $x^{1/2}$
Andrew Henderson
I study the roots laws and this is one of them:
$$\sqrt x = x^{1/2}$$
I don't know how simplify the $x^{1/2}$, what I mean is...
If for example:
$$x^{-3}=1 \cdot 1/x \cdot 1/x \cdot 1/x = 1/x^3$$
How do I simplify:
$$x^{1/2} = ?$$
Edit:
This edit is written to explain the meaning of simplify:
We all know that $3^3=1*3*3*3 = 27$
The 1*3*3*3 above is a simplification for $3^3$, in my question I ask if there is a way to simplify $x^{1/2}$
$\endgroup$ 63 Answers
$\begingroup$There is no easy way to simplify $x^{\frac12}$, except by writing it as $x^{\frac12}=\sqrt x$
$\endgroup$ 2 $\begingroup$Reading between the lines are you trying to justify the result?
Consider:
$x^a \times x^a= x^1$
Using power laws you get $x^{2a}=x^1$
Comparing powers $a=\frac{1}{2}$
...but $\sqrt{x}\times \sqrt{x}=x$
so to preserve the power laws $x^{1/2}=\sqrt{x}$.
I think this is as simple as the identity gets but I like the expression by @logicmonkey for $x\neq0$
$\endgroup$ 1 $\begingroup$You might occasionally want to write it as $\frac {{x}}{{\sqrt x}}$
$\endgroup$ 5