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How to decode this time string [duplicate]

Writer Mia Lopez

I got this string from an api After looking at it I realized it was a dat/time

20220112201146

I then decoded it by hand to be

2022(Y)01(M)12(D)20(H)11(M)46(S)

How would I slice everything up to be Y:M:D:H:M:S? Example:

2022:01:12:20:11:46

And then add 80 mins to it?

4

1 Answer

Extract the various parts (year, month, day, etc) via regex, transform it to ISO 8601 format, parse it to a Date instance, then add 80 minutes

const str = "20220112201146"
const rx = /(\d{4})(\d{2})(\d{2})(\d{2})(\d{2})(\d{2})/
const iso8601 = str.replace(rx, "$1-$2-$3T$4:$5:$6")
console.log("iso8601:", iso8601)
const date = new Date(iso8601)
console.log("original date:", date.toLocaleString())
date.setMinutes(date.getMinutes() + 80)
console.log("future date:", date.toLocaleString())
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