How is the law of contraposition a tautology?
Matthew Harrington
I recently started the study of Aristotelian logic in Math class. I wanted to ask (as the title suggests) why the law of contraposition is a tautology. My book states that a tautology is a statement which is true for the all the values of the variables included.
I ask this because I constructed the truth table for the law, but the statement didn't satisfy the definition of a tautology. It would be much appreciated if anyone would help me understand this, thanks.
$\endgroup$ 21 Answer
$\begingroup$Just fill in the truth table like this:
P | Q | P → Q | ~Q → ~P | (P → Q) ↔ (~Q → ~P)
––|–––|–––––––|––––––––––|––––––––––––––––––––
T | T | T | T | T
T | F | F | F | T
F | T | T | T | T
F | F | T | T | TAs you see, these two have identical truth values, and they are logically equivalent. It means that (P → Q) ↔ (~Q → ~P) is a tautology, not ~Q → ~P. If two things are logically equivalent, they create a tautology when in the form of a biconditional.
You might find this link helpful:
$\endgroup$