How do I input color values into the Adobe color picker in hexadecimal?
Emily Wong
I have some C# code (though it could be any language) and I am trying to copy the colors used therein into an Illustrator design.
Here's the code:
private static readonly Dictionary<string, SolidColorBrush> _DefaultModeColours = new Dictionary<string, SolidColorBrush>
{ { "null", new SolidColorBrush(Color.FromArgb(0xFF, 0x00, 0x00, 0x00)) }, { "lean-back", new SolidColorBrush(Color.FromArgb(0xFF, 0xFF, 0x69, 0xB4)) }, { "respite", new SolidColorBrush(Color.FromArgb(0xFF, 0xDB, 0x00, 0x00)) }, { "purposeful", new SolidColorBrush(Color.FromArgb(0xFF, 0xFF, 0xFF, 0x00)) }, { "opportunistic", new SolidColorBrush(Color.FromArgb(0xFF, 0x0C, 0x06, 0x40)) }, { "orienting", new SolidColorBrush(Color.FromArgb(0xFF, 0x92, 0xBC, 0xE5)) }
};The colors are specified using hexadecimal numbers for the ARGB values. In Illustrator I have the following color chooser:
I could fire up a calculator and convert each of the (nonobvious) hex values into decimal, but I imagine there is an easy way to change the Illustrator settings for the document to use hex values. Is there? If so where do I set it?
1 Answer
You double click the fill or the stroke from the left side menu. Then you can input the hex.
Then you will see a popup exactly like Photoshop
You can then type in the Hex number (by the # symbol).
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