Velvet Star Monitor

Standout celebrity highlights with iconic style.

general

How can I submit a form using JavaScript?

Writer Sophia Terry

I have a form with id theForm which has the following div with a submit button inside:

<div> <button type="submit" class='input_submit' onClick="placeOrder()">Place Order </button>
</div>

When clicked, the function placeOrder() is called. The function changes the innerHTML of the above div to be "processing ..." (so the submit button is now gone).

The above code works, but now the problem is that I can't get the form to submit! I've tried putting this in the placeOrder() function:

document.theForm.submit();

But that doesn't work.

How can I get the form to submit?

5

10 Answers

Set the name attribute of your form to "theForm" and your code will work.

2

You can use...

document.getElementById('theForm').submit();

...but don't replace the innerHTML. You could hide the form and then insert a processing... span which will appear in its place.

var form = document.getElementById('theForm');
form.style.display = 'none';
var processing = document.createElement('span');
processing.appendChild(document.createTextNode('processing ...'));
form.parentNode.insertBefore(processing, form);
5

It works perfectly in my case.

document.getElementById("form1").submit();

Also, you can use it in a function as below:

function formSubmit()
{ document.getElementById("form1").submit();
}
4
document.forms["name of your form"].submit();

or

document.getElementById("form id").submit();

You can try any of this...this will definitely work...

I will leave the way I do to submit the form without using the name tag inside the form:

HTML

<button type="submit" onClick="placeOrder(this.form)">Place Order</button>

JavaScript

function placeOrder(form){ form.submit();
}

You can use the below code to submit the form using JavaScript:

document.getElementById('FormID').submit();
<html> <body> <p>Enter some text in the fields below, and then press the "Submit form" button to submit the form.</p> <form action="/action_page.php"> First name: <input type="text" name="fname"><br> Last name: <input type="text" name="lname"><br><br> <input type="button" onclick="myFunction()" value="Submit form"> </form> <script> function myFunction() { document.getElementById("myForm").submit(); } </script> </body>
</html>
1

HTML

<!-- change id attribute to name -->
<form method="post" action="yourUrl" name="theForm"> <button onclick="placeOrder()">Place Order</button>
</form>

JavaScript

function placeOrder () { document.theForm.submit()
}
3

If your form does not have any id, but it has a class name like theForm, you can use the below statement to submit it:

document.getElementsByClassName("theForm")[0].submit();
1

I have came up with an easy resolve using a simple form hidden on my website with the same information the users logged in with. Example: If you want a user to be logged in on this form, you can add something like this to the follow form below.

<input type="checkbox" name="autologin" />

As far I know I am the first to hide a form and submit it via clicking a link. There is the link submitting a hidden form with the information. It is not 100% safe if you don't like auto login methods on your website with passwords sitting on a hidden form password text area...

Okay, so here is the work. Let’s say $siteid is the account and $sitepw is password.

First make the form in your PHP script. If you don’t like HTML in it, use minimal data and then echo in the value in a hidden form. I just use a PHP value and echo in anywhere I want pref next to the form button as you can't see it.

PHP form to print

$hidden_forum = '
<form action="./forum/ucp.php?mode=login" method="post"> <input type="text" name="username" value="'.strtolower($siteid).'" title="Username" /> <input type="password" name="password" value="'.$sitepw.'" title="Password" />
</form>';

PHP and link to submit form

<?php print $hidden_forum; ?>
<pre><a href="#forum" onClick="javascript: document.getElementById('alt_forum_login').submit();">Forum</a></pre>
3