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Getting pointer for first entry in an array

Writer Sophia Terry

I want to get pointer of first entry in the array. This is how I tried

int[] Results = { 1, 2, 3, 4, 5 };
unsafe
{ int* FirstResult = Results[0];
}

Get following compilation error. Any ideas how to fix it?

You can only take the address of an unfixed expression inside of a fixed statement initializer

2

3 Answers

Try this:

unsafe
{ fixed (int* FirstResult = &Results[0]) { }
}

The error codes are magic to get the answer - search for error code (CS0212 in your case) and you get explanation with proposed fix in a lot of case.

Search:

Result:

Code from the page:

 unsafe public void mf() { // Null-terminated ASCII characters in an sbyte array sbyte[] sbArr1 = new sbyte[] { 0x41, 0x42, 0x43, 0x00 }; sbyte* pAsciiUpper = &sbArr1[0]; // CS0212 // To resolve this error, delete the previous line and // uncomment the following code: // fixed (sbyte* pAsciiUpper = sbArr1) // { // String szAsciiUpper = new String(pAsciiUpper); // } }

The error message is pretty clear. You can refer to MSDN.

unsafe static void MyInsaneCode()
{ int[] Results = { 1, 2, 3, 4, 5 }; fixed (int* first = &Results[0]) { /* something */ }
}

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