For the command pm.plot_posterior of pymc3
Andrew Mclaughlin
Usually, I find we use the pm.binomial() and so forth. and using the pm.plot_posterior we get the Discrete graph, my question is why my graph I have to get is a curve? Could someone enlighten me?
I want to get:
But I get the graph:
1 Answer
The kind argument accepts either "kde" (default for continuous) or "hist".
import arviz as az
az.plot_posterior(trace, kind="hist")Please see the documentation.
1