Find the solution of the initial value problem $y' = 2x / (1 + 2y)$, $y(2) = 0$ in explicit form.
Matthew Martinez 
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This is what I've done so far:
The answer given is $y = \sqrt{x^2 - \frac{15}{4}} - \frac{1}{2}$ so that would mean I'll have to reject $y = -\sqrt{x^2 - \frac{15}{4}} - \frac{1}{2}$ but how do I go about doing that?
Can someone give me a hint or two on how to reject $y = -\sqrt{x^2 - \frac{15}{4}} - \frac{1}{2}$?
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$\begingroup$The negative root does not satisfy the initial condition.
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