I am learning C++ templates on vs2015 community.Here is my code, I want to define a template class and call the member function in the main() function.

template <typename T>
class Arithmetic { T _a; T _b; Arithmetic() {};
public Arithmetic(T a, T b) :_a(a), _b(b) {}; T max const() { return _a + _b; }; T minus const() { return _a - _b; };
};
int main() { Arithmetic<int> ar(5,6); cout << ar.max() << endl;
}

When I build this program, I get error at the last line. It says:

Expression preceding parentheses of apparent call must have (pointer-to-) function type

What should I do?

1

4 Answers

For anyone else this might also be because of redefinition of a method or property name. i.e a property and method might have the same name

2

The error indicates trying to call a function max() that is not defined as a function. Change parenthesis after const keyword to after the identifier max:

T max const()...

to

T max() const ...

• Add required header inclusion and using
• Add : after public
• Move const to proper position

#include <iostream>
using std::cout;
using std::endl;
template <typename T>
class Arithmetic { T _a; T _b; Arithmetic() {};
public: Arithmetic(T a, T b) :_a(a), _b(b) {}; T max() const { return _a + _b; }; T minus() const { return _a - _b; };
};
int main() { Arithmetic<int> ar(5,6); cout << ar.max() << endl;
}

0

This problem can also be caused if you are sending non-constant values into the max method.

This is the syntax for max:

constexpr const T& max (const T& a, const T& b, Compare comp);

2

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