Example:

>>> convert('CamelCase')
'camel_case'

4

30 Answers

Camel case to snake case

import re
name = 'CamelCaseName'
name = re.sub(r'(?<!^)(?=[A-Z])', '_', name).lower()
print(name) # camel_case_name

If you do this many times and the above is slow, compile the regex beforehand:

pattern = re.compile(r'(?<!^)(?=[A-Z])')
name = pattern.sub('_', name).lower()

To handle more advanced cases specially (this is not reversible anymore):

def camel_to_snake(name): name = re.sub('(.)([A-Z][a-z]+)', r'\1_\2', name) return re.sub('([a-z0-9])([A-Z])', r'\1_\2', name).lower()
print(camel_to_snake('camel2_camel2_case')) # camel2_camel2_case
print(camel_to_snake('getHTTPResponseCode')) # get_http_response_code
print(camel_to_snake('HTTPResponseCodeXYZ')) # http_response_code_xyz

To add also cases with two underscores or more:

def to_snake_case(name): name = re.sub('(.)([A-Z][a-z]+)', r'\1_\2', name) name = re.sub('__([A-Z])', r'_\1', name) name = re.sub('([a-z0-9])([A-Z])', r'\1_\2', name) return name.lower()

Snake case to camel case

name = 'snake_case_name'
name = ''.join(word.title() for word in name.split('_'))
print(name) # SnakeCaseName

19

There's an inflection library in the package index that can handle these things for you. In this case, you'd be looking for inflection.underscore():

>>> inflection.underscore('CamelCase')
'camel_case'

16

I don't know why these are all so complicating.

for most cases, the simple expression ([A-Z]+) will do the trick

>>> re.sub('([A-Z]+)', r'_\1','CamelCase').lower()
'_camel_case'
>>> re.sub('([A-Z]+)', r'_\1','camelCase').lower()
'camel_case'
>>> re.sub('([A-Z]+)', r'_\1','camel2Case2').lower()
'camel2_case2'
>>> re.sub('([A-Z]+)', r'_\1','camelCamelCase').lower()
'camel_camel_case'
>>> re.sub('([A-Z]+)', r'_\1','getHTTPResponseCode').lower()
'get_httpresponse_code'

To ignore the first character simply add look behind (?!^)

>>> re.sub('(?!^)([A-Z]+)', r'_\1','CamelCase').lower()
'camel_case'
>>> re.sub('(?!^)([A-Z]+)', r'_\1','CamelCamelCase').lower()
'camel_camel_case'
>>> re.sub('(?!^)([A-Z]+)', r'_\1','Camel2Camel2Case').lower()
'camel2_camel2_case'
>>> re.sub('(?!^)([A-Z]+)', r'_\1','getHTTPResponseCode').lower()
'get_httpresponse_code'

If you want to separate ALLCaps to all_caps and expect numbers in your string you still don't need to do two separate runs just use | This expression ((?<=[a-z0-9])[A-Z]|(?!^)[A-Z](?=[a-z])) can handle just about every scenario in the book

>>> a = re.compile('((?<=[a-z0-9])[A-Z]|(?!^)[A-Z](?=[a-z]))')
>>> a.sub(r'_\1', 'getHTTPResponseCode').lower()
'get_http_response_code'
>>> a.sub(r'_\1', 'get2HTTPResponseCode').lower()
'get2_http_response_code'
>>> a.sub(r'_\1', 'get2HTTPResponse123Code').lower()
'get2_http_response123_code'
>>> a.sub(r'_\1', 'HTTPResponseCode').lower()
'http_response_code'
>>> a.sub(r'_\1', 'HTTPResponseCodeXYZ').lower()
'http_response_code_xyz'

It all depends on what you want so use the solution that best suits your needs as it should not be overly complicated.

nJoy!

4

Avoiding libraries and regular expressions:

def camel_to_snake(s): return ''.join(['_'+c.lower() if c.isupper() else c for c in s]).lstrip('_')

>>> camel_to_snake('ThisIsMyString')
'this_is_my_string'

7

stringcase is my go-to library for this; e.g.:

>>> from stringcase import pascalcase, snakecase
>>> snakecase('FooBarBaz')
'foo_bar_baz'
>>> pascalcase('foo_bar_baz')
'FooBarBaz'

6

I think this solution is more straightforward than previous answers:

import re
def convert (camel_input): words = re.findall(r'[A-Z]?[a-z]+|[A-Z]{2,}(?=[A-Z][a-z]|\d|\W|$)|\d+', camel_input) return '_'.join(map(str.lower, words))
# Let's test it
test_strings = [ 'CamelCase', 'camelCamelCase', 'Camel2Camel2Case', 'getHTTPResponseCode', 'get200HTTPResponseCode', 'getHTTP200ResponseCode', 'HTTPResponseCode', 'ResponseHTTP', 'ResponseHTTP2', 'Fun?!awesome', 'Fun?!Awesome', '10CoolDudes', '20coolDudes'
]
for test_string in test_strings: print(convert(test_string))

Which outputs:

camel_case
camel_camel_case
camel_2_camel_2_case
get_http_response_code
get_200_http_response_code
get_http_200_response_code
http_response_code
response_http
response_http_2
fun_awesome
fun_awesome
10_cool_dudes
20_cool_dudes

The regular expression matches three patterns:

1. [A-Z]?[a-z]+: Consecutive lower-case letters that optionally start with an upper-case letter.
2. [A-Z]{2,}(?=[A-Z][a-z]|\d|\W|$): Two or more consecutive upper-case letters. It uses a lookahead to exclude the last upper-case letter if it is followed by a lower-case letter.
3. \d+: Consecutive numbers.

By using re.findall we get a list of individual "words" that can be converted to lower-case and joined with underscores.

6

Personally I am not sure how anything using regular expressions in python can be described as elegant. Most answers here are just doing "code golf" type RE tricks. Elegant coding is supposed to be easily understood.

def to_snake_case(not_snake_case): final = '' for i in xrange(len(not_snake_case)): item = not_snake_case[i] if i < len(not_snake_case) - 1: next_char_will_be_underscored = ( not_snake_case[i+1] == "_" or not_snake_case[i+1] == " " or not_snake_case[i+1].isupper() ) if (item == " " or item == "_") and next_char_will_be_underscored: continue elif (item == " " or item == "_"): final += "_" elif item.isupper(): final += "_"+item.lower() else: final += item if final[0] == "_": final = final[1:] return final
>>> to_snake_case("RegularExpressionsAreFunky")
'regular_expressions_are_funky'
>>> to_snake_case("RegularExpressionsAre Funky")
'regular_expressions_are_funky'
>>> to_snake_case("RegularExpressionsAre_Funky")
'regular_expressions_are_funky'

7

''.join('_'+c.lower() if c.isupper() else c for c in "DeathToCamelCase").strip('_')
re.sub("(.)([A-Z])", r'\1_\2', 'DeathToCamelCase').lower()

Here's my solution:

def un_camel(text): """ Converts a CamelCase name into an under_score name. >>> un_camel('CamelCase') 'camel_case' >>> un_camel('getHTTPResponseCode') 'get_http_response_code' """ result = [] pos = 0 while pos < len(text): if text[pos].isupper(): if pos-1 > 0 and text[pos-1].islower() or pos-1 > 0 and \ pos+1 < len(text) and text[pos+1].islower(): result.append("_%s" % text[pos].lower()) else: result.append(text[pos].lower()) else: result.append(text[pos]) pos += 1 return "".join(result)

It supports those corner cases discussed in the comments. For instance, it'll convert getHTTPResponseCode to get_http_response_code like it should.

4

I don't get idea why using both .sub() calls? :) I'm not regex guru, but I simplified function to this one, which is suitable for my certain needs, I just needed a solution to convert camelCasedVars from POST request to vars_with_underscore:

def myFunc(...): return re.sub('(.)([A-Z]{1})', r'\1_\2', "iTriedToWriteNicely").lower()

It does not work with such names like getHTTPResponse, cause I heard it is bad naming convention (should be like getHttpResponse, it's obviously, that it's much easier memorize this form).

2

For the fun of it:

>>> def un_camel(input):
... output = [input[0].lower()]
... for c in input[1:]:
... if c in ('ABCDEFGHIJKLMNOPQRSTUVWXYZ'):
... output.append('_')
... output.append(c.lower())
... else:
... output.append(c)
... return str.join('', output)
...
>>> un_camel("camel_case")
'camel_case'
>>> un_camel("CamelCase")
'camel_case'

Or, more for the fun of it:

>>> un_camel = lambda i: i[0].lower() + str.join('', ("_" + c.lower() if c in "ABCDEFGHIJKLMNOPQRSTUVWXYZ" else c for c in i[1:]))
>>> un_camel("camel_case")
'camel_case'
>>> un_camel("CamelCase")
'camel_case'

8

Using regexes may be the shortest, but this solution is way more readable:

def to_snake_case(s): snake = "".join(["_"+c.lower() if c.isupper() else c for c in s]) return snake[1:] if snake.startswith("_") else snake

2

This is not a elegant method, is a very 'low level' implementation of a simple state machine (bitfield state machine), possibly the most anti pythonic mode to resolve this, however re module also implements a too complex state machine to resolve this simple task, so i think this is a good solution.

def splitSymbol(s): si, ci, state = 0, 0, 0 # start_index, current_index ''' state bits: 0: no yields 1: lower yields 2: lower yields - 1 4: upper yields 8: digit yields 16: other yields 32 : upper sequence mark ''' for c in s: if c.islower(): if state & 1: yield s[si:ci] si = ci elif state & 2: yield s[si:ci - 1] si = ci - 1 state = 4 | 8 | 16 ci += 1 elif c.isupper(): if state & 4: yield s[si:ci] si = ci if state & 32: state = 2 | 8 | 16 | 32 else: state = 8 | 16 | 32 ci += 1 elif c.isdigit(): if state & 8: yield s[si:ci] si = ci state = 1 | 4 | 16 ci += 1 else: if state & 16: yield s[si:ci] state = 0 ci += 1 # eat ci si = ci print(' : ', c, bin(state)) if state: yield s[si:ci]
def camelcaseToUnderscore(s): return '_'.join(splitSymbol(s)) 

splitsymbol can parses all case types: UpperSEQUENCEInterleaved, under_score, BIG_SYMBOLS and cammelCasedMethods

I hope it is useful

1

Take a look at the excellent Schematics lib

It allows you to created typed data structures that can serialize/deserialize from python to Javascript flavour, eg:

class MapPrice(Model): price_before_vat = DecimalType(serialized_name='priceBeforeVat') vat_rate = DecimalType(serialized_name='vatRate') vat = DecimalType() total_price = DecimalType(serialized_name='totalPrice')

So many complicated methods... Just find all "Titled" group and join its lower cased variant with underscore.

>>> import re
>>> def camel_to_snake(string):
... groups = re.findall('([A-z0-9][a-z]*)', string)
... return '_'.join([i.lower() for i in groups])
...
>>> camel_to_snake('ABCPingPongByTheWay2KWhereIsOurBorderlands3???')
'a_b_c_ping_pong_by_the_way_2_k_where_is_our_borderlands_3'

If you don't want make numbers like first character of group or separate group - you can use ([A-z][a-z0-9]*) mask.

A horrendous example using regular expressions (you could easily clean this up :) ):

def f(s): return s.group(1).lower() + "_" + s.group(2).lower()
p = re.compile("([A-Z]+[a-z]+)([A-Z]?)")
print p.sub(f, "CamelCase")
print p.sub(f, "getHTTPResponseCode")

Works for getHTTPResponseCode though!

Alternatively, using lambda:

p = re.compile("([A-Z]+[a-z]+)([A-Z]?)")
print p.sub(lambda x: x.group(1).lower() + "_" + x.group(2).lower(), "CamelCase")
print p.sub(lambda x: x.group(1).lower() + "_" + x.group(2).lower(), "getHTTPResponseCode")

EDIT: It should also be pretty easy to see that there's room for improvement for cases like "Test", because the underscore is unconditionally inserted.

Lightely adapted from who use generators.

def uncamelize(s): buff, l = '', [] for ltr in s: if ltr.isupper(): if buff: l.append(buff) buff = '' buff += ltr l.append(buff) return '_'.join(l).lower()

This simple method should do the job:

import re
def convert(name): return re.sub(r'([A-Z]*)([A-Z][a-z]+)', lambda x: (x.group(1) + '_' if x.group(1) else '') + x.group(2) + '_', name).rstrip('_').lower()

• We look for capital letters that are precedeed by any number of (or zero) capital letters, and followed by any number of lowercase characters.
• An underscore is placed just before the occurence of the last capital letter found in the group, and one can be placed before that capital letter in case it is preceded by other capital letters.
• If there are trailing underscores, remove those.
• Finally, the whole result string is changed to lower case.

(taken from here, see working example online)

1

Here's something I did to change the headers on a tab-delimited file. I'm omitting the part where I only edited the first line of the file. You could adapt it to Python pretty easily with the re library. This also includes separating out numbers (but keeps the digits together). I did it in two steps because that was easier than telling it not to put an underscore at the start of a line or tab.

Step One...find uppercase letters or integers preceded by lowercase letters, and precede them with an underscore:

Search:

([a-z]+)([A-Z]|[0-9]+)

Replacement:

\1_\l\2/

Step Two...take the above and run it again to convert all caps to lowercase:

Search:

([A-Z])

Replacement (that's backslash, lowercase L, backslash, one):

\l\1

I was looking for a solution to the same problem, except that I needed a chain; e.g.

"CamelCamelCamelCase" -> "Camel-camel-camel-case"

Starting from the nice two-word solutions here, I came up with the following:

"-".join(x.group(1).lower() if x.group(2) is None else x.group(1) \ for x in re.finditer("((^.[^A-Z]+)|([A-Z][^A-Z]+))", "stringToSplit"))

Most of the complicated logic is to avoid lowercasing the first word. Here's a simpler version if you don't mind altering the first word:

"-".join(x.group(1).lower() for x in re.finditer("(^[^A-Z]+|[A-Z][^A-Z]+)", "stringToSplit"))

Of course, you can pre-compile the regular expressions or join with underscore instead of hyphen, as discussed in the other solutions.

Concise without regular expressions, but HTTPResponseCode=> httpresponse_code:

def from_camel(name): """ ThisIsCamelCase ==> this_is_camel_case """ name = name.replace("_", "") _cas = lambda _x : [_i.isupper() for _i in _x] seq = zip(_cas(name[1:-1]), _cas(name[2:])) ss = [_x + 1 for _x, (_i, _j) in enumerate(seq) if (_i, _j) == (False, True)] return "".join([ch + "_" if _x in ss else ch for _x, ch in numerate(name.lower())])

Without any library :

def camelify(out): return (''.join(["_"+x.lower() if i<len(out)-1 and x.isupper() and out[i+1].islower() else x.lower()+"_" if i<len(out)-1 and x.islower() and out[i+1].isupper() else x.lower() for i,x in enumerate(list(out))])).lstrip('_').replace('__','_')

A bit heavy, but

CamelCamelCamelCase -> camel_camel_camel_case
HTTPRequest -> http_request
GetHTTPRequest -> get_http_request
getHTTPRequest -> get_http_request

Very nice RegEx proposed on this site:

(?<!^)(?=[A-Z])

If python have a String Split method, it should work...

In Java:

String s = "loremIpsum";
words = s.split("(?<!^)(?=[A-Z])");

1

Just in case someone needs to transform a complete source file, here is a script that will do it.

# Copy and paste your camel case code in the string below
camelCaseCode =""" cv2.Matx33d ComputeZoomMatrix(const cv2.Point2d & zoomCenter, double zoomRatio) { auto mat = cv2.Matx33d::eye(); mat(0, 0) = zoomRatio; mat(1, 1) = zoomRatio; mat(0, 2) = zoomCenter.x * (1. - zoomRatio); mat(1, 2) = zoomCenter.y * (1. - zoomRatio); return mat; }
"""
import re
def snake_case(name): s1 = re.sub('(.)([A-Z][a-z]+)', r'\1_\2', name) return re.sub('([a-z0-9])([A-Z])', r'\1_\2', s1).lower()
def lines(str): return str.split("\n")
def unlines(lst): return "\n".join(lst)
def words(str): return str.split(" ")
def unwords(lst): return " ".join(lst)
def map_partial(function): return lambda values : [ function(v) for v in values]
import functools
def compose(*functions): return functools.reduce(lambda f, g: lambda x: f(g(x)), functions, lambda x: x)
snake_case_code = compose( unlines , map_partial(unwords), map_partial(map_partial(snake_case)), map_partial(words), lines
)
print(snake_case_code(camelCaseCode))

Wow I just stole this from django snippets. ref

Pretty elegant

camelcase_to_underscore = lambda str: re.sub(r'(?<=[a-z])[A-Z]|[A-Z](?=[^A-Z])', r'_\g<0>', str).lower().strip('_')

Example:

camelcase_to_underscore('ThisUser')

Returns:

'this_user'

REGEX DEMO

3

def convert(name): return reduce( lambda x, y: x + ('_' if y.isupper() else '') + y, name ).lower()

And if we need to cover a case with already-un-cameled input:

def convert(name): return reduce( lambda x, y: x + ('_' if y.isupper() and not x.endswith('_') else '') + y, name ).lower()

Not in the standard library, but I found this module that appears to contain the functionality you need.

2

If you use Google's (nearly) deterministic Camel case algorithm, then one does not need to handle things like HTMLDocument since it should be HtmlDocument, then this regex based approach is simple. It replace all capitals or numbers with an underscore. Note does not handle multi digit numbers.

import re
def to_snake_case(camel_str): return re.sub('([A-Z0-9])', r'_\1', camel_str).lower().lstrip('_')

def convert(camel_str): temp_list = [] for letter in camel_str: if letter.islower(): temp_list.append(letter) else: temp_list.append('_') temp_list.append(letter) result = "".join(temp_list) return result.lower()

Use: str.capitalize() to convert first letter of the string (contained in variable str) to a capital letter and returns the entire string.

Example: Command: "hello".capitalize() Output: Hello

1