1. Create a 4x7 table using an array and fill up the array with random values.
2. Then find the column number (X) where the last row contains the smallest value.

3. Then find ratio_1, ratio_2, ratio_3 where

   • ratio_1 = the value from last column of 1st row / the value from column X of 1st row
   • ratio_2 = the value from last column of 2nd row / the value from column X of 2nd row
   • ratio_3 = the value from last column of 3rd row / the value from column X of 3rd row

Notice that, X is the column number that you find in step 2.

2

2 Answers

from random import random
data = [ [int(random()*10) for j in range(7)] for i in range(4)
]

Output

data = [ [2, 7, 8, 9, 8, 1, 1], [5, 7, 0, 9, 1, 8, 6], [6, 5, 8, 3, 7, 4, 8], [2, 5, 4, 0, 9, 8, 7]
]

This should work:

from random import random
grid = [[], [], [], []]
for x in range(4): for y in range(7): grid[x].append(random())
last_numbers = [grid[0][6], grid[1][6], grid[2][6], grid[3][6]]
column_number = last_numbers.index(max(last_numbers))
ratio_1 = grid[3][0] / grid[column_number][0]
ratio_2 = grid[3][1] / grid[column_number][1]
ratio_3 = grid[3][2] / grid[column_number][2]

1

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